# How do you solve 4^(-3x)=0.25?

Jul 26, 2016

$x = \frac{1}{3}$

#### Explanation:

Since $0.25 = \frac{1}{4} = {4}^{-} 1$

you can write the equivalent equation:

${4}^{- 3 x} = {4}^{-} 1$

then

$- 3 x = - 1$

$\frac{\cancel{- 3} x}{\cancel{- 3}} = - \frac{1}{-} 3$

$x = \frac{1}{3}$