**Part 1:** #4>3x+3#

#4>3x+3#

#color(white)("XXXX")#subtract 3 from both sides

#1>3x#

#color(white)("XXXX")#divide both sides by 3

#1/3>x#

**Part 2:** #9<=−5x+3#

#9<=-5x+3#

#color(white)("XXXX")#subtract 3 from both sides

#6<=-5x#

#color(white)("XXXX")#divide both sides by #(-5)# remembering to reverse the inequality orientation because of the negative division.

#-6/5>=x#

**Part 3:** combining with **or**

If it is only necessary for

#color(white)("XXXX")##x<1/3#

**or**

#color(white)("XXXX")##x<=-6/5#

then

it is only necessary for

#color(white)("XXXX")##x<1/3#

#color(white)("XXXX")##color(white)("XXXX")#since #(x<=-6/5)# is a subset of #(x<1/3)#)