How do you solve 4 - (-7-k) > 2 (k+3)?

Feb 7, 2017

$k < 5$

Explanation:

Solve like you would a standard multi-step equation.

Since it seems you are new to multi-step equations, it helps to first write the equation as

$4 + \left(- 1\right) \left(- 7 - k\right) > 2 \left(k + 3\right)$
Distribute the coefficient to the binomial (a fancy term for "multiply -1 by -7-k and 2 by k+3) to remove the brackets.

You get $4 + 7 + k > 2 k + 6 \text{ }$ Pretty straightforward from here.

$11 + k > 2 k + 6$

$k > 2 k - 5$

$- k > - 5$

THE LAST STEP IS CRUCIAL. If you ever multiply or divide by a negative, real number than you must switch the inequality sign.

The final answer is $k < 5$