How do you solve #4 sqrt(3m^2-15)=14?#?

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Answer 1 · 2015-07-20T14:54:38

#color(blue)(m approx 3.01#

# 4sqrt(3m^2−15)=14#

Squaring both sides:
# (4sqrt(3m^2−15))^2=14^2#

#16 * (3m^2-15) =196#

#48m^2 - 240 = 196#

#48m^2 = 436#

#m^2 = 436/48#
#m^2 = 9.08#

#color(blue)(m approx 3.01#