# How do you solve 4 - sqrt(3x +1) = 5 and find any extraneous solutions?

Jun 29, 2016

This equation has no real solutions.

#### Explanation:

To solve such equation first we move roots to left side, and number to right side.

$4 - \sqrt{3 x + 1} = 5$

$- \sqrt{3 x + 1} = 1$

$\sqrt{3 x + 1} = - 1$

Now you can see that the equation has no real solutions because there are no real numbers whose square root (or any other root of an even degree) is negative.