# How do you solve 4(u+1)^2=18?

Jun 22, 2016

$u = - 1 \pm \frac{3 \sqrt{2}}{2}$

#### Explanation:

$4 {\left(u + 1\right)}^{2} = 18 \leftarrow$ Divide both sides by 4

${\left(u + 1\right)}^{2} = \frac{18}{4} \leftarrow$ Square root both sides

$u + 1 = \pm \sqrt{\frac{18}{4}} \leftarrow$ Subtract 1 from both sides

$u = \pm \sqrt{\frac{18}{4}} - 1 \leftarrow$ simplify the square root

$u = - 1 \pm \frac{\sqrt{2 \times {3}^{2}}}{\sqrt{{2}^{2}}} \leftarrow$

$u = - 1 \pm \frac{3 \sqrt{2}}{2}$