How do you solve #4(x-1)^2-3=25#?

1 Answer
Aug 27, 2017

Answer:

#x=1+-sqrt7#

Explanation:

#"isolate "(x-1)^2" on the left side"#

#"add 3 to both sides"#

#4(x-1)^2cancel(-3)cancel(+3)=25+3#

#rArr4(x-1)^2=28#

#"divide both sides by 4"#

#cancel(4)/cancel(4)(x-1)^2=28/4#

#rArr(x-1)^2=7#

#color(blue)"take the square root of both sides"#

#sqrt((x-1)^2)=+-sqrt7larr" note plus or minus"#

#rArrx-1=+-sqrt7#

#"add 1 to both sides"#

#xcancel(-1)cancel(+1)=+-sqrt7+1#

#rArrx=1+-sqrt7#