How do you solve #-4/x = 1/3x - 10 #?

1 Answer
Jan 25, 2016

Answer:

Put everything on an equal denominator and solve for x.

Explanation:

The lowest common denomiator for this equation would be 3x

#-4/x# = #1/3x# - 10

#-(4(3))/(3x)# = #(x(x))/(3x# - #(10(3x))/(3x)#

Now that everything's on an equal denomiator we can get rid of the denominators and solve the resulting quadratic equation.

-12 = #x^2# - 30x

0 = #x^2# - 30x + 12

After solving with the quadratic formula, you'll get approximate solutions of x = 29.5945 and x = 0.4055. However, your teacher may want you to leave the answer In radical form, so beware of that.