How do you solve #(4 + x) / 5<=8#?

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Answer 1 · 2018-03-05T00:03:39

See a solution process below:

First, multiply each side of the inequality by #color(red)(5)# to eliminate the fraction while keeping the equation balanced:

#color(red)(5) xx (4 + x)/5 <= color(red)(5) xx 8#

#cancel(color(red)(5)) xx (4 + x)/color(red)(cancel(color(black)(5))) <= 40#

#4 + x <= 40#

Now, subtract #color(red)(4)# from each side of the equation to solve for #x# while keeping the equation balanced:

#4 - color(red)(4) + x <= 40 - color(red)(4)#

#0 + x <= 36#

#x <= 36#