# How do you solve 4(y-3)=48?

Jun 15, 2017

$y = 15$

#### Explanation:

First, divide both sides of the equation by $4$. You could also start by distributing the $4$ into the parentheses but that will only make this problem take more time.

$y - 3 = \frac{48}{4} = 12$

Add $3$ to both sides.

$y = 15$

Jun 15, 2017

$y = 15$

#### Explanation:

$\text{divide both sides of the equation by 4}$

$\frac{4}{4} \left(y - 3\right) = \frac{48}{4}$

$\Rightarrow y - 3 = 12$

$\text{add 3 to both sides}$

$y \cancel{- 3} \cancel{+ 3} = 12 + 3$

$\Rightarrow y = 15$

$\textcolor{b l u e}{\text{As a check}}$

$4 \left(15 - 3\right) = 4 \times 12 = 48 = \text{ right side}$

$\Rightarrow y = 15 \text{ is the solution}$