# How do you solve #4(y-3)=48#?

##### 2 Answers

Jun 15, 2017

#### Answer:

#### Explanation:

First, divide both sides of the equation by

#y-3=48/4=12#

Add

#y=15#

Jun 15, 2017

#### Answer:

#### Explanation:

#"divide both sides of the equation by 4"#

#4/4(y-3)=48/4#

#rArry-3=12#

#"add 3 to both sides"#

#ycancel(-3)cancel(+3)=12+3#

#rArry=15#

#color(blue)"As a check"#

#4(15-3)=4xx12=48=" right side"#

#rArry=15" is the solution"#