# How do you solve 49x ^ { 2} - 56x + 15= 0?

May 28, 2017

$\frac{5}{7} \mathmr{and} \frac{3}{7}$

#### Explanation:

$y = 49 {x}^{2} - 56 x + 15 = 0$
$y ' = {x}^{2} - 56 x + 735 = 0$ (ac = 49(15) = 735)
$x 1 = \frac{35}{a} = \frac{35}{49} = \frac{5}{7}$ and $x 2 = \frac{21}{a} = \frac{21}{49} = \frac{3}{7}$