How do you solve #4a-2>14#?

1 Answer
Dec 23, 2016

Answer:

#a > 4#

Explanation:

The first step in solving this problem is to use the necessary mathematics to isolate the #a# term on one side of the inequality and the constants on the other side of the inequality while keeping the inequality balanced:

#4a - 2 + color(red)(2) > 14 + color(red)(2)#

#4a + (- 2 + color(red)(2)) > 14 + color(red)(2)#

#4a + (0) > 14 + color(red)(2)#

#4a > 14 + 2#

Now combine the like terms, in this case the constants:

#4a > 16#

Finally, solve for #a# while keeping the inequality balanced:

#(4a)/color(red)(4) > 16/color(red)(4)#

#(color(red)(cancel(color(black)(4)))a)/color(red)(cancel(color(black)(4))) > 4#

#a > 4#