# How do you solve 4abs(r+7)+3=59?

Mar 17, 2017

$r = 7$ or $r = - 21$

#### Explanation:

As $4 | r + 7 | + 3 = 59$

$4 | r + 7 | = 59 - 3 = 56$

or $| r + 7 | = \frac{56}{4} = 14$

Now $| r + 7 |$ stands for modulus or absolute value of $r + 7$. And hence as it is equal to $14$,

we either have $r + 7 = 14$ i.e. $r = 14 - 7 = 7$

or $r + 7 = - 14$ i.e, $r = - 14 - 7 = - 21$