How do you solve $4 k - 4 - 3 k > 13 - 7 k - 1 + 8$ $4k-4-3k >13-7k-1+8$ ?

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Answer 1 · 2016-07-30T10:02:11

$k > 3$ $k>3$

Treat inequalities exactly the same as an equation except if you multiply or divide by a negative number the sign changes around.

$4 k - 4 - 3 k > 13 - 7 k - 1 + 8 simplify both sides$ $4k-4-3k >13-7k-1+8" simplify both sides"$

$k - 4 > 20 - 7 k$ $k -4 > 20-7k$

$k + 7 k > 20 + 4 variables on one side$ $k + 7k >20+4 " variables on one side"$

$8 k > 24$ $8k >24$

$k > 3$ $k>3$

How do you solve 4k−4−3k>13−7k−1+84k-4-3k >13-7k-1+8?