# How do you solve 4sqrt(3m^2-15)=4?

Feb 20, 2017

$m = \sqrt{\frac{16}{3}}$ and $- \sqrt{\frac{16}{3}}$

#### Explanation:

Divide 4 on both sides:

$\left(\frac{4}{4}\right) \sqrt{3 {m}^{2} - 15} = \left(\frac{4}{4}\right)$

The fours cancel leaving:

$\sqrt{3 {m}^{2} - 15} = 1$

Square both sides to get rid of the square root. Note that when you do this, it will become positive or negative 1

$3 {m}^{2} - 15 = 1$

$3 {m}^{2} = 16$
${m}^{2} = \frac{16}{3}$
$m = \sqrt{\frac{16}{3}}$ and $- \sqrt{\frac{16}{3}}$