How do you solve $4 tan x - 7 = 3 tan x - 6$ $4tanx-7=3tanx-6$ for $0 \leq x \leq 2 π$ $0<=x<=2pi$ ?

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How do you solve $4 tan x - 7 = 3 tan x - 6$ $4tanx-7=3tanx-6$ for $0 \leq x \leq 2 π$ $0<=x<=2pi$ ?

1 Answer

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Answer 1 · 2016-12-02T15:39:54

$\frac{π}{4}, \frac{5 π}{4}$ $pi/4, (5pi)/4$

Explanation:

4tan x - 7 = 3tan x - 6.
4tan x - 3tan x = - 6 + 7
tan x = 1
Use trig table and unit circle
tan x = 1 --> 2 solution arcs -->
arc $x = \frac{π}{4}$ $x = pi/4$ and arc $x = \frac{π}{4} + π = \frac{5 π}{4}$ $x = pi/4 + pi = (5pi)/4$ .
Answers for $(0, 2 π)$ $(0, 2pi)$
$\frac{π}{4} and \frac{5 π}{4}$ $pi/4 and (5pi)/4$

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How do you solve $4 tan x - 7 = 3 tan x - 6$ $4tanx-7=3tanx-6$ for $0 \leq x \leq 2 π$ $0<=x<=2pi$ ?

1 Answer

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How do you solve 4tanx-7=3tanx-64tanx−7=3tanx−64tanx-7=3tanx-6 for 0<=x<=2pi0≤x≤2π0<=x<=2pi?

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How do you solve $4 tan x - 7 = 3 tan x - 6$ $4tanx-7=3tanx-6$ for $0 \leq x \leq 2 π$ $0<=x<=2pi$ ?