How do you solve #-4x > 12#?

2 Answers
Apr 30, 2018

Answer:

#x<-3#

Explanation:

it is given

#-4x>12#

So

#=> 4x<-12 " "# [#div# by a negative #-># flip the sign]

#x< (-12)/4 => x<-3#

so the solution of this question is #x<-3#.

Apr 30, 2018

Answer:

#x<-3#

Explanation:

Given: #-4x>12#.

Divide by #4# on both sides.

#(-4x)/4>12/4#

#-x>3#

Switch signs. That means that the inequality sign flips as well.

#=>x<-3#