# How do you solve 4x ≥ -16 and x + 1 ≤ 0?

Jul 20, 2015

Solve
$4 x \ge - 16$ (1)
$x + 1 \le 0$ (2)

#### Explanation:

(1) -->$x \ge - 4$

(2) --> $x \le - 1$

---------------|-4============|-1-------|0---------------

Answer by closed interval: [-4, -1], meaning the 2 critical points are included in the solution set.