How do you solve #4x^2 - 16 = 0# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Don't Memorise Sep 29, 2015 #color(blue)(x=+-2# Explanation: #4x^2−16=0# #4x^2−4^2=0# Here #4# is common to both terms #4x^2−4^2=4(x^2-4)# #4(x^2-4)=0# #x^2-4=0# #x^2=4# #x=sqrt4# #color(blue)(x=+-2# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 2809 views around the world You can reuse this answer Creative Commons License