How do you solve #4x + 2y > - 8#?

1 Answer
Sep 24, 2017

Refer to the explanation.

Explanation:

Solve:

#4x+2y> -8#

This inequality represents a linear equation in standard form, but as an inequality. If we solve for #y#, it will be in slope-intercept form: #y=mx+b#, where #m# is the slope, and #b# is the y-intercept (value of #y# when #x=0#. This makes it easier to graph.

Subtract #4x# from both sides.

#2y> -4x-8#

Divide both sides by #2#.

#y> -(4x)/2-8/2#

Simplify.

#y> -2x-4#

The graph will have a straight, dashed line to indicate that it represents the boundary of the inequality, but is not part of the inequality, and the area above the line is shaded to represent the inequality.

graph{4x+2y> -8 [-10, 10, -5, 5]}