# How do you solve #4x - 3y = 22 # and #4x + 5y = 6#?

##### 1 Answer

#### Explanation:

Set it out in a column like so:

#4x - 3y = 22#

#4x + 5y = 6#

Then subtract the second equation from the first one to get:

#-8y = 16#

which can be simplified to

#-y = 2" "# or#" "y = -2#

This, in turn, can be used to work out the

#4x -10 = 6#

#4x = 16#

#x = 4#

Hopefully this helps...