# How do you solve -4x+8<1/2x +3?

Nov 7, 2015

• Multiply by $2$ to get rid of denominators and isolate the $x$'s
• Divide by the coifficient of x on both sides
$x > \frac{10}{9}$

#### Explanation:

Start off by multiplying by $2$ to get rid of denominators
$- 4 x + 8 < \frac{1}{2} x + 3 \to - 8 x + 16 < x + 6$
NOTE: We are multiplying by $2$ since $2$ is the highest common denominator.

Isolate the x's:
$- 8 x - x < 6 - 16$

$- 9 x < - 10$
$\frac{- 9 x}{-} 9 > - \frac{10}{-} 9 \to \frac{\cancel{- 9} x}{\cancel{- 9}} > \frac{- 10}{-} 9 \to x > \frac{10}{9}$