# How do you solve 4y+4x=0 and -y-2=x?

Jul 16, 2016

This set of equations has no solutions.

#### Explanation:

$\left\{\begin{matrix}4 y + 4 x = 0 \\ - y - 2 = x\end{matrix}\right.$

If we divide the first equation by $4$ we get: $y + x = 0$.
The second equation can be transformed to: $y + x = - 2$, so we get the system:

$\left\{\begin{matrix}y + x = 0 \\ y + x = - 2\end{matrix}\right.$

If we substract both sides of the second equation from the respective sides of the first we get:

$0 = 2$

which is false and means that the set has no solutions.