How do you solve #5(1+10^6x) = 12#?
1 Answer
Oct 18, 2015
Rearrange and take logs if necessary to find
Explanation:
I'm not sure whether your question appears as intended, so I will answer both interpretations:
Divide both sides by
#1+10^6x = 12/5#
Subtract
#10^6x = 7/5#
Divide both sides by
#x = 7/(5*10^6) = 0.0000014#
Divide both sides by
#1+10^(6x) = 12/5#
Subtract
#10^(6x) = 7/5#
Take common logarithms of both sides to get:
#6x = log(7/5)#
Divide both sides by
#x = log(7/5)/6 ~~ 0.02435#