# How do you solve -5(2b+7)+b< -b-11?

Nov 23, 2016

$b > - 3$

#### Explanation:

First, expand the term in parenthesis:

$- 10 b - 35 + b < - b - 11$

Next, combine like terms:

$- 9 b - 35 < - b - 11$

Now, isolate the $b$ terms on one side of the inequality and the constants on the other side of the inequality while keeping everything balanced:

$- 9 b - 35 + 35 + b < - b - 11 + 35 + b$

$- 9 b + b < - 11 + 35$

$- 8 b < 24$

Finally we solve for $b$ by dividing each side of the inequality by $- 8$. However, remember to "flip" or reverse the inequality because we are dividing by a negative number:

$\frac{- 8 b}{- 8} > \frac{24}{- 8}$

$b > - 3$