# How do you solve 5(2g-3)-6> -2(g-6)+3?

Oct 1, 2016

$g > 3$

#### Explanation:

$5 \left(2 g - 3\right) - 6 > - 2 \left(g - 6\right) + 3$

$10 g - 15 - 6 > - 2 g + 12 + 3 \textcolor{w h i t e}{a a a}$ Distribute

$10 g - 21 \textcolor{w h i t e}{{a}^{1} a a} > - 2 g + 15 \textcolor{w h i t e}{a a a}$ Combine like terms

$\textcolor{w h i t e}{a} 10 g - 21 > - 2 g + 15$
$+ 2 g \textcolor{w h i t e}{a a a a {a}^{1} a a} + 2 g \textcolor{w h i t e}{a a a a a a a}$ Add 2g to both sides

$12 g - 21 \textcolor{w h i t e}{a} > \textcolor{w h i t e}{a a a} 15$
$\textcolor{w h i t e}{a a a} + 21 \textcolor{w h i t e}{a} > \textcolor{w h i t e}{1} + 21 \textcolor{w h i t e}{a a a a}$ Add 21 to both sides

$\frac{12 g}{12} > \frac{36}{12} \textcolor{w h i t e}{a a a a a}$ Divide both sides by 12

$g > 3$