How do you solve #5(2g-3)-6> -2(g-6)+3#?

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Answer 1 · 2016-10-01T12:29:13

#g>3#

#5(2g-3)-6 > -2(g-6)+3#

#10g-15-6 > -2g+12+3color(white)(aaa)# Distribute

#10g-21 color(white)(a^1aa)> -2g+15color(white)(aaa)# Combine like terms

#color(white)a10g-21 > -2g +15#
#+2gcolor(white)(aaaaa^1aa)+2gcolor(white)(aaaaaaa)# Add 2g to both sides

#12g -21color(white)a>color(white)(aaa)15#
#color(white)(aaa)+21 color(white)a> color(white)1+21color(white)(aaaa)# Add 21 to both sides

#(12g)/12 > 36/12color(white)(aaaaa)# Divide both sides by 12

#g>3#