# How do you solve 5-2x>27 ?

##### 1 Answer
Jan 18, 2017

See the entire solution process below:

#### Explanation:

First, subtract $\textcolor{red}{5}$ from each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$5 - \textcolor{red}{5} - 2 x > 27 - \textcolor{red}{5}$

$0 - 2 x > 22$

$- 2 x > 22$

Now, divide each side of the inequality by $\textcolor{b l u e}{- 2}$ to solve for $x$ while keeping the inequality balanced.

However, when dealing with inequalities and multiplying or dividing by a negative term we must also reverse the inequality sign:

$\frac{- 2 x}{\textcolor{b l u e}{- 2}} \textcolor{red}{<} \frac{22}{\textcolor{b l u e}{- 2}}$

$\frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{- 2}}} x}{\cancel{\textcolor{b l u e}{- 2}}} \textcolor{red}{<} - 11$

$x < - 11$