How do you solve #-5(2x-6)+8x=22#?
3 Answers
Explanation:
Hope this helps :)
Explanation:
Check the answer by plugging it into the original equation:
Explanation:
#"distribute and simplify left side of equation"#
#-10x+30+8x=22#
#rArr-2x+30=22#
#"subtract 30 from both sides"#
#-2xcancel(+30)cancel(-30)=22-30#
#rArr-2x=-8#
#"divide both sides by "-2#
#(cancel(-2) x)/cancel(-2)=(-8)/(-2)#
#rArrx=4#
#color(blue)"As a check"# Substitute this value into the left side of the equation and if equal to the right side then it is the solution.
#-5(8-6)+(8xx4)=-10+32=22=" right side"#
#rArrx=4" is the solution"#