How do you solve #5(3x + 12) = -15#?

1 Answer
Apr 28, 2018

Answer:

#x=-5#

Explanation:

#"divide both sides by "5#

#cancel(5)/cancel(5)(3x+12)=(-15)/5#

#rArr3x+12=-3#

#"subtract 12 from both sides"#

#3xcancel(+12)cancel(-12)=-3-12#

#rArr3x=-15#

#"divide both sides by 3"#

#(cancel(3) x)/cancel(3)=(-15)/3#

#rArrx=-5#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#5(-15+12)=5xx-3=-15=" right side"#

#rArrx=-5" is the solution"#