How do you solve #-5<=4r+3#?
1 Answer
May 3, 2018
Explanation:
#"isolate "4r" by subtracting 3 from both sides"#
#-5-3<=4rcancel(+3)cancel(-3)#
#rArr-8<=4r#
#"divide both sides by 4"#
#(-8)/4<=cancel(4)/cancel(4) r#
#rArr-2<=r" or "r>= -2#
#r in[-2,oo)larrcolor(blue)"in interval notation"#
