How do you solve #-5< \frac{8x - 5}{6} < 7#? Algebra Linear Inequalities and Absolute Value Compound Inequalities 1 Answer Dani · Stefan V. Jun 5, 2018 Undo the operations surrounding #x# by applying the inverses to both sides in the reverse order. Explanation: Multiply all sides by #6#: #-30 < 8x - 5 < 42# Add #5#: #-25 < 8x < 47# Divide all sides by #8#: #-25/8 < x < 47/8# Answer link Related questions How do you solve compound inequalities? What is an example of an inequality that uses "and" and what inequality uses "or"? How do you graph #-40 \le y < 60# on a number line? How do you solve for x in #3x-5 < x + 9 \le 5x + 13 #? How do you solve #9-2x \le 3 or 3x+10 \le 6-x#? How do you solve for b given #6+b<8 or b+6 \ge 6#? How do you graph #x ≥ 4# or #x > -4#? How do you solve the compound inequality #-20≤-6m-2≤58# and graph its solution? How do you graph #-53<9v+1<-26#? How do you graph this inequality: #15<x<30#? See all questions in Compound Inequalities Impact of this question 1039 views around the world You can reuse this answer Creative Commons License