# How do you solve 5b-1>=-11?

Apr 15, 2017

$b \ge - 2$

#### Explanation:

$5 b - 1 \ge - 11$

Add $1$ to both sides

$5 b \setminus \cancel{\textcolor{red}{- 1 + 1}} \ge - 11 + 1$

Simplify what you can

$5 b \ge - 10$

Divide both sides by $5$ so that $b$ stands alone

$\frac{\setminus \cancel{5} b}{\setminus} \cancel{5} \ge - \frac{10}{5}$

$b \ge - \frac{2 \times \cancel{5}}{\cancel{5}}$

$\Rightarrow b \ge - 2$