How do you solve #5b-1>=-11#?

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Answer 1 · 2017-04-15T06:35:48

#b>=-2#

#5b-1>=-11#

Add #1# to both sides

#5b\cancelcolor(red)(-1+1)>=-11+1#

Simplify what you can

#5b>=-10#

Divide both sides by #5# so that #b# stands alone

#(\cancel(5)b)/\cancel(5)>=-10/5#

#b>=-(2xxcancel5)/cancel5#

#rArrb>=-2#