How do you solve #(5w - 8 )/ 3 = 4w + 2#?
1 Answer
Feb 17, 2016
w = - 2
Explanation:
To eliminate the fraction multiply both sides by 3
#(cancel(3)(5w-8))/cancel(3) = 3(4w + 2) # hence 3(4w + 2 ) = 5w - 8
so 12w + 6 = 5w - 8
subtract 5w from both sides : 12w + 6 - 5w = 5w - 8 - 5w
7w + 6 = - 8subtract 6 from both sides : 7w + 6 - 6 = - 8 - 6
7w = - 14finally divide both sides by 7
#( cancel(7) w)/cancel(7) = -14/7 rArr w = - 2#