How do you solve #(5w - 8 )/ 3 = 4w + 2#?

1 Answer
Feb 17, 2016

Answer:

w = - 2

Explanation:

To eliminate the fraction multiply both sides by 3

#(cancel(3)(5w-8))/cancel(3) = 3(4w + 2) #

hence 3(4w + 2 ) = 5w - 8

so 12w + 6 = 5w - 8

subtract 5w from both sides : 12w + 6 - 5w = 5w - 8 - 5w
7w + 6 = - 8

subtract 6 from both sides : 7w + 6 - 6 = - 8 - 6
7w = - 14

finally divide both sides by 7

#( cancel(7) w)/cancel(7) = -14/7 rArr w = - 2#