How do you solve #5x^2 = 100# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Joel Kindiak Oct 3, 2015 Make the LHS quadratic and RHS = 0 Explanation: #5x^2 = 100# #x^2=20 # #x^2-20=0 # #(x+sqrt(20))(x-sqrt(20))=0# #(x+2sqrt(5))(x-2sqrt(5))=0# #x=-2sqrt(5)# or #x=2sqrt(5)# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 3005 views around the world You can reuse this answer Creative Commons License