How do you solve #5x^2-3x+7=7# by factoring?

2 Answers
Apr 13, 2018

Answer:

#x=3/5#
#x=0#

Explanation:

#5x^2-3x+7=7# Combine like terms:
#5x^2-3x=0# Factor out #x#:
#(x)(5x-3)=0#
Using the zero product property,
#x=0#
and
#5x-3=0# Isolate #x# and coefficients:
#5x=3# Isolate #x#:
#x=3/5#

Apr 13, 2018

Answer:

#x=0" or "x=3/5#

Explanation:

#"subtract 7 from both sides"#

#rArr5x^2-3x=0larrcolor(blue)"in standard form"#

#"take out a "color(blue)"common factor "x#

#rArrx(5x-3)=0#

#"equate each factor to zero and solve for x"#

#rArrx=0#

#5x-3=0rArrx=3/5#