How do you solve 5x^2-3x+7=7 by factoring?

2 Answers
Apr 13, 2018

x=3/5
x=0

Explanation:

5x^2-3x+7=7 Combine like terms:
5x^2-3x=0 Factor out x:
(x)(5x-3)=0
Using the zero product property,
x=0
and
5x-3=0 Isolate x and coefficients:
5x=3 Isolate x:
x=3/5

Apr 13, 2018

x=0" or "x=3/5

Explanation:

"subtract 7 from both sides"

rArr5x^2-3x=0larrcolor(blue)"in standard form"

"take out a "color(blue)"common factor "x

rArrx(5x-3)=0

"equate each factor to zero and solve for x"

rArrx=0

5x-3=0rArrx=3/5