Question

How do you solve `5x^2-3x+7=7` by factoring?

Answer 1

`x=3/5`
`x=0`

Explanation:

`5x^2-3x+7=7` Combine like terms:
`5x^2-3x=0` Factor out `x`:
`(x)(5x-3)=0`
Using the zero product property,
`x=0`
and
`5x-3=0` Isolate `x` and coefficients:
`5x=3` Isolate `x`:
`x=3/5`

Answer 2

`x=0" or "x=3/5`

Explanation:

`"subtract 7 from both sides"`

`rArr5x^2-3x=0larrcolor(blue)"in standard form"`

`"take out a "color(blue)"common factor "x`

`rArrx(5x-3)=0`

`"equate each factor to zero and solve for x"`

`rArrx=0`

`5x-3=0rArrx=3/5`