Question

How do you solve `5x^2= 4-19x` by factoring?

Answer 1

See explanation

Explanation:

We have that

`5x^2+19x-4=0=>5x^2+20x-x-4=0=>5x(x+4)-(x+4)=0=>(5x-1)(x+4)=0=>x=-4 or x=1/5`