# How do you solve 5x^2+5=-13x using the quadratic formula?

Jun 3, 2017

$x = - \frac{13}{10} + \sqrt{69} , \mathmr{and} - \frac{13}{10} - \sqrt{69}$

#### Explanation:

Firstly, in any quadratic equation, you want to get it in the form $a {x}^{2} + b x + c$.

To do that, add $13 x$ to both sides.

$5 {x}^{2} + 13 x + 5 = 0$

Now, we can get the following ; $a = 5 , b = 13 , c = 5$

The quadratic formula is this : $\frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

Substitute the values

$\frac{- 13 \pm \sqrt{{13}^{2} - \left(4\right) \left(5\right) \left(5\right)}}{\left(2\right) \left(5\right)}$

$\frac{- 13 + \sqrt{69}}{10}$

$- \frac{13}{10} + \sqrt{69} , - \frac{13}{10} - \sqrt{69}$