How do you solve #5x+2=6#?

1 Answer
Jim G.
Mar 6, 2017

#x=4/5#

Explanation:

Isolate 5x by subtracting 2 from both sides of the equation.

#5xcancel(+2)cancel(-2)=6-2#

#rArr5x=4#

To solve for x, divide both sides by 5

#(cancel(5) x)/cancel(5)=4/5#

#rArrx=4/5#

#color(blue)"As a check"#

Substitute this value into the left side and if equal to the right side then it is the solution.

#(cancel(5)^1xx4/cancel(5)^1)+2=4+2=6=" right side"#

#rArrx=4/5" is the solution"#

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