Question

How do you solve `5x^3 - 320 x = 0`?

Answer 1

`x=±8`

Explanation:

`5x^3-320x=0`

`cancel(5)cancel(x)^3=cancel(320)cancel(x)`

`x^2=64`

`sqrt (x^2)=sqrt64`

`sqrt(x^2)=sqrt 8^2`

`x=±8`