# How do you solve #−5x + 8 <= x − 4#?

##### 1 Answer

Aug 15, 2015

#### Answer:

#### Explanation:

Isolate

#-5x + 8 - x <= color(red)(cancel(color(black)(x))) - color(red)(cancel(color(black)(x))) - 4#

#-6x + 8 <= -4#

Next, add

#-6x + color(red)(cancel(color(black)(8))) - color(red)(cancel(color(black)(8))) <= -4 - 8#

#-6x <= -12#

FInally, divide both sides by **do not forget** that you need to change the sign of the inequality when you're multiplying or dividing by a *negative number*

#(color(red)(cancel(color(black)(-6)))x)/color(red)(cancel(color(black)(-6))) color(red)(>=) ((-12))/((-6))#

#x >= color(green)(2)#

So, for any value of *greater to or equal than*