How do you solve #6^(-2a) = 6^(2-3a)#?

2 Answers
José F.
Feb 27, 2016

#6^(-2a)=6^(2-3a)#

#a^b=a^c => b=c#

Just solve

#-2a=2-3a#

#a=2#

Johnson Z.
Feb 27, 2016

#a=2#

Explanation:

#1#. Since the bases are the same on both sides of the equation, the exponents are equal to each other. We can represent this relationship using an equation.

#6^color(blue)(-2a)=6^color(orange)(2-3a)#

#color(blue)(-2a)=color(orange)(2-3a)#

#2#. Solve for #a#.

#-2a# #color(red)(+3a)=2-3a# #color(red)(+3a)#

#color(green)(a=2)#

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