How do you solve #6( 2x + 5) < - 78#?
1 Answer
Apr 10, 2018
Explanation:
#"distribute the parenthesis"#
#rArr12x+30< -78#
#"subtract 30 from both sides"#
#12xcancel(+30)cancel(-30)< -78-30#
#rArr12x< -108#
#"divide both sides by 12"#
#(cancel(12) x)/cancel(12)<(-108)/12#
#rArrx< -9" is the solution"#
