# How do you solve  −6<3(x−2) ≤ 8?

Apr 19, 2018

Solution : $0 < x \le \frac{14}{3} \mathmr{and} \left(0 , \frac{14}{3}\right]$

#### Explanation:

$- 6 < 3 \left(x - 2\right) \le 8$ , dividing by $3$ on all sides we get,

$- 2 < \left(x - 2\right) \le \frac{8}{3}$ , adding $2$ on all sides we get,

$0 < x \le \frac{8}{3} + 2 \mathmr{and} 0 < x \le \frac{14}{3}$

Solution : $0 < x \le \frac{14}{3} \mathmr{and} \left(0 , \frac{14}{3}\right]$ [Ans]