How do you solve #6 – 3(x – 3) ≤ 6(x – 4)#?

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Answer 1 · 2018-04-04T03:37:50

#x >= 4 1/3#

Here's what I did:

#6-3(x-3)<=6(x-4)#

We solve inequalities similarly to equations.

The first thing we want to do is distribute:
#6-3x+9<=6x-24#

Add #6# to the #9#:
#15-3x<=6x-24#

Now let's add #3x# to both sides of the inequality:
#15 <= 9x - 24#

And add #24# to both sides of the inequality:
#39 <= 9x#

Now we divide both sides by #9#:
#4 1/3 <= x#

And put #x# on the left side of the inequality to make it more clear:
#x >= 4 1/3#

Hope this helps!