# How do you solve 6 – 3(x – 3) ≤ 6(x – 4)?

Apr 4, 2018

$x \ge 4 \frac{1}{3}$

Here's what I did:

#### Explanation:

$6 - 3 \left(x - 3\right) \le 6 \left(x - 4\right)$

We solve inequalities similarly to equations.

The first thing we want to do is distribute:
$6 - 3 x + 9 \le 6 x - 24$

Add $6$ to the $9$:
$15 - 3 x \le 6 x - 24$

Now let's add $3 x$ to both sides of the inequality:
$15 \le 9 x - 24$

And add $24$ to both sides of the inequality:
$39 \le 9 x$

Now we divide both sides by $9$:
$4 \frac{1}{3} \le x$

And put $x$ on the left side of the inequality to make it more clear:
$x \ge 4 \frac{1}{3}$

Hope this helps!