How do you solve #6-3(x-3)<6(x-4)#?

1 Answer
Nov 5, 2015

Answer:

13/3<x

Explanation:

First you distribute the -3(x-3) to get
6-3x+9
then you distribute the other side to get
6x-24
then set up your inequality again to get
6-3x+9<6x-24
now solve for the x
add the 6 and 9 on the left side to equal 15-3x
this comes out to
15-3x<6x-24
add the 24 to the 15 and add the 3x to the 6x to get
39/9<x
which reduces to
13/3<x