How do you solve #(6\times 4) + b = 60#?

1 Answer
Dec 5, 2017

Answer:

See a solution process below:

Explanation:

First, execute the multiplication operation within the parenthesis:

#(color(red)(6) xx color(red)(4)) + b = 60#

#24 + b = 60#

Now, subtract #color(red)(24)# from each side of the equation to solve for #b# while keeping the equation balanced:

#24 - color(red)(24) + b = 60 - color(red)(24)#

#0 + b = 36#

#b = 36#