How do you solve 6^x+10=47? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Monzur R. Feb 19, 2017 x=log_6 37 Explanation: 6^x+10=47 6^x = 37 log_6 6^x=log_6 37 loga^b=bloga xlog_6 6 =log_6 37 log_a a=1 x = log_6 37 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1448 views around the world You can reuse this answer Creative Commons License