Question

How do you solve `6^x+10=47`?

Answer 1

`x=log_6 37`

Explanation:

`6^x+10=47`

`6^x = 37`

`log_6 6^x=log_6 37`

`loga^b=bloga`

`xlog_6 6 =log_6 37`

`log_a a=1`

`x = log_6 37`