How do you solve #6(x+3)=48# using the distributive property?

1 Answer
Jul 31, 2017

Answer:

#x=5#

Explanation:

#"multiply the terms in the bracket by 6"#

#rArr6x+18=48#

#"subtract 18 from both sides"#

#6xcancel(+18)cancel(-18)=48-18#

#rArr6x=30#

#"divide both sides by 6"#

#(cancel(6) x)/cancel(6)=30/6#

#rArrx=5#

#color(blue)"As a check"#

substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#6(5+3)=6xx8=48=" right side"#

#rArrx=5" is the solution"#