How do you solve #6(y+1)-5=7#?

1 Answer
Jan 6, 2017

Answer:

We use the order of BODMAS(Brackets Open Division Multiplication Addition Subtraction) to solve any kind of sum,algerba,eqn etc.
eg like this one. Acc to the priority of BODMAS we do operations(+,-,*,/)

Explanation:

I'm solving it here:

#6(y+1) -5=7#

#6(y+1) = 12#

#6y+ 6 =12#

#6y = 6#

#therefore y= 1#