# How do you solve (6g - 5)^(1/3) + 2 = -3 ?

May 19, 2018

$g = - 20$

#### Explanation:

${\left(6 g - 5\right)}^{\frac{1}{3}} + 2 = - 3$

Is the same thing as:

$\sqrt[3]{6 g - 5} + 2 = - 3$

$\sqrt[3]{6 g - 5} = - 5$

Cube both sides of the equation:

${\left(\sqrt[3]{6 g - 5}\right)}^{3} = {\left(- 5\right)}^{3}$

$6 g - 5 = - 125$

$6 g = - 120$

$g = - 20$