How do you solve #(6g - 5)^(1/3) + 2 = -3 #?

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Answer 1 · 2018-05-19T16:51:55

#g = -20#

#(6g-5)^(1/3) + 2 = -3#

Is the same thing as:

#root(3)(6g-5) + 2 = -3#

#root(3)(6g-5) = -5#

Cube both sides of the equation:

#(root(3)(6g-5))^3 = (-5)^3#

#6g-5 = -125#

#6g = -120#

#g = -20#